. Joseph and Peter can complete a work in 20 hours and 25 hours respectively.
Find : (i) work done by both together in 4 hrs.
(ii) work left after both worked together for 4 hrs.
(iii) time taken by Peter to complete the remaining work.
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. Joseph and Peter can complete a work in 20 hours and 25 hours respectively.
Find : (i) work done by both together in 4 hrs.
(ii) work left after both worked together for 4 hrs.
(iii) time taken by Peter to complete the remaining work.
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Answer:
Joseph can do a work in 20 hours
Peter can do the same work in 25 hours
Now Joseph’s 1 hour’s work = 1/20
And Peter’s 1 hour’s work = 1/25
Both’s 1 hour’s work = 1/20 + 1/25
= (5 + 4)/100
= 9/100
(i) Both’s 4 hours work = 9/100 × 4 = 9/25
(ii) Work left = 1 – 9/25
= (25 – 9)/25
= 16/25
(iii) Peter can do 16/25 work in = 25 × 16/25
= 16 hours