justification of 75 degree angle
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Sol. (i) Steps of Construction :
1. Draw a ray OA.
2. Construct ∠AOB=60o
3. Construct ∠AOP=90o
4. Bisect ∠BOP so that
∠BOQ=12∠BOP
=12(∠AOP−∠AOB)
=12(90o−60o)=12×30o=15o
So, we obtain
∠AOQ=∠AOB+∠BOQ
= 60º + 15º = 75º
Verification :
On measuring ∠AOQ, with the protractor, we find ∠AOQ=75o
i hope its hlp you