Lead acetate instantaneously forms a white solid when dilute HCl is added to it.
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Lead acetate instantaneously forms a white solid when dilute HCl is added to it.
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Answer:
IT IS A DOUBLE DISPLACEMENT REACTION.
Answer:
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Explanation:
Lead acetate [Pb(CH3COO)2] reacts with dilute hydrochloric acid (HCl) to form lead chloride (PbCl2) and acetic acid (CH3COOH). It is a double displacement reaction as both the reactants exchange ions to form new products. The equation can be written as:
Pb(CH3COO)2+2HCl→PbCl2+2CH3COOH