Let a(x) ∈ R[x]. When a(x) is divided by x − 2 the remainder is 5. When a(x) is divided by x − 3 the remainder is 11. Find the remainder when a(x) is divided by x 2 − 5x + 6
Let a(x) ∈ R[x]. When a(x) is divided by x − 2 the remainder is 5. When a(x) is divided by x − 3 the remainder is 11. Find the remainder when a(x) is divided by x 2 − 5x + 6
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Step-by-step explanation:
remainder =6
hopefully help you