Let f (x) = x^2 + xg' (1) +g" (2) and g(x) = f(1) x^2 + xf'(x) + f” (x) then f (g(1)) is equal to=
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Let f (x) = x^2 + xg' (1) +g" (2) and g(x) = f(1) x^2 + xf'(x) + f” (x) then f (g(1)) is equal to=
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[tex] \huge\star{\underline {\underline{\pink{Q}{uestion}}}}\star\: [/tex]
A door of length 2 m. and breadth 1 m. is fitted in a wall. The length of the wall is 4.5 m. and the breadth is 3.6 m.
Find the cost of white washing the wall, if the rate of white washing the wall is 20 per m².
[tex] \huge\star{\underline{\underline{\pink {A}{nswer}}}}\star\: [/tex]
White washing of the wall has to be white washed excluding the area of door.
[tex]\red {=》} [/tex] Area of the wall including door = length × breadth
[tex]\red {=》} [/tex] 4.5 m. × 3.6 m. = 16.2 m²
[tex]\red {=》} [/tex] Area of rectangular door = length × breadth
[tex]\red {=》} [/tex] 2m. × 1m. = 2 m²
[tex] \huge{\underline{\underline{Now,}}} [/tex]
Area of wall excluding door = Area of wall including door - Area of rectangular door
[tex]\red {=》} [/tex] 16.2 m² - 2 m²
[tex]\red {=》} [/tex] 14.2 m²
[tex] \huge {\underline {\underline {Given,}}} [/tex]
The rate of white washing of 1 m² the wall = 20
The rate of white washing 14.2 m² the wall = 20 × 14.2
[tex]\red {===》} [/tex] 284
[tex] \huge\green{\underline {\underline{\mathtt {Final\: Answer}}}} [/tex]
The cost of white washing
of the wall excluding door
is 284
@SpammingKing here
Answer:
kinna sona tenu rabb ne bnaya !