5kg having vol of 5lit when converted into steam at ntp occupies a vol 8.405 m3 .if latent heat of vaporization of water is 540 k cal/lg .find its internal latent heat ?
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5kg having vol of 5lit when converted into steam at ntp occupies a vol 8.405 m3 .if latent heat of vaporization of water is 540 k cal/lg .find its internal latent heat ?
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Answer:
Total heat energy required = change in internal energy + work done
Here, heat energy required is the latent heat of vaporization.
Change in internal energy=538−168(0.239)=538−40.152=497.848cal
( 1J=0.239cal )
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Answer:
497.848cal
Explanation:
Change in internal energy
= 538 - 168 × 0.239
= 538- 40.152
= 497.848cal