∆LMN~∆RST, LM=3,MN=4,ST=12,find RS
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Answer:
Given, △LMN∼△RST, A(△LMN)=100sq.cm, A(△RST)=144sq.cm, and LM=5cm,
By the theorem of areas of similar triangles,
A(△RST)
A(△LMN)
=
RS
2
LM
2
144
100
=
RS
2
25
RS
2
=25×
100
144
=36
RS=6 cm
Answer:
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Step-by-step explanation:
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