integration of secxcosecx/log(tanx)
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Answer:log(log tan x)
Step-by-step explanation:
secxcosecxdx/log (tan x)
If we take log tan x=t
1/tanx×sec^2xdx=dt
dx=tanx dt/sec^2 x
(sec x cosecx tanxdt)/sec^2x t
cancelling everything we get
Integral(dt/t)=log t
log(log tan x)
Answer:
hlo hii
I don't know sorry