a spring of spring constant 5 N/m is compressed to 6mm,the restoring frorce is Z×10^-2 N where Z is
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a spring of spring constant 5 N/m is compressed to 6mm,the restoring frorce is Z×10^-2 N where Z is
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Answer:
4*12 = 48 ( 40+8.) similarly, 12 * 11= 12 12= 1 ( 2 + 1) 2 = 132 and so on.
Answer:
The answer is 132..............