Meena is three times as old as Leena . after 5 years , she will be as twice as age of Leena , find there present ages
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Meena is three times as old as Leena . after 5 years , she will be as twice as age of Leena , find there present ages
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Answer :-
Let present age of meena = X years
Let present age of meena's mother =Y years
After five years age of meena =(x + 5) years
After five years age of meen's mother =(Y +5) years
According to question
[tex]y = 4x - - - (1)[/tex]
[tex]y + 5 = 3(x + 5) - - - (2)[/tex]
Put (1) in (2) , we get
[tex]4x + 5 = 3x + 15[/tex]
[tex]4x - 3x = 15 - 5[/tex]
[tex]x = 10[/tex]
[tex]y = 40[/tex]
Meena's present age =10 years
Meena's mother's present age =40 years