density of 2.05M solutions of acetic acid in water is 1.02g/ml.Find molality of same solution
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Answer:
m = 2.285mol kg⁻¹
Explanation:
molality - m
molarity - M
Density - d
M₂ - Molecular mass - CH₃COOH = 60g
m = 1000M / 1000d - MM₂
m = 1000 × 2.05 / (1000 × 1.02) - (2.05 × 60)
m = 2050 / 1020 - 123
m = 2050 / 897
m = 2.285mol kg⁻¹