Given : Na(s) + 1/2 Cl2 + NaCI ; Delta f Hº = -411.2 kJ/mol
Na(s) → Na(g) Delta sub Hº = 108.4 kJ/mol
Na(g) → Na^+(g) +e^-(g) ; Delta IE H° = 496 kJ/mol
Cl2(g) → 2Cl(g) ; Delta BDE Hº=242kJ/mol
Cl(g) + e^-(g) → CI^-(g) ; Delta Eg Hº = -348.6 kJ/mol
By using the data find the Delta r H of the following
reaction
Na^+ (g) + Cl^- (g) → Na^+Cl^-(s) ; Delta r H = ?
- 740 kJ
-836 kJ
-945 kJ
-788 kJ
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