if the energy of an electron in the first orbit of h-atom is –313.6 kcal/mol, then energy of electron in the second orbit of helium will be :
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if the energy of an electron in the first orbit of h-atom is –313.6 kcal/mol, then energy of electron in the second orbit of helium will be :
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Answer: E = -313. 6kcal Z2/n2
Explanation:
E = -313. 6 x 2^2/2^2
E = - 313.6 KCal/mole