NO SPAM ..NO PLAGIARISM..
DEEP EXPLANATION NEEDED..
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NO SPAM ..NO PLAGIARISM..DEEP EXPLANATION NEEDED..
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Step-by-step explanation:
let secx + tanx = t
differentiation w r t x
→ sec²x + secx tanx = dt/dx
→ secx(secx + tanx) = dt/dx
→ secx(t) = dt/dx
→secx.dx = 1/t.dt ________ eq 1
Now according to the question we have
(secx)
integration of ____________.dx
(secx + tanx)
replacing value according to eq 1
→ ! 1/(t⁹'²).1/t.dt
→ ! 1/t¹¹'².dt
→ ! (t)-¹¹'².dt
→ [(t)-⁹'² ]/(-9/2) + c
→ -2/9(secx + tanx) + c
here this " ! " symbol I have used for integration