No spam!!!
Correct answers accepted!!
Content required!!!
Thanks!!!
Share
No spam!!!
Correct answers accepted!!
Content required!!!
Thanks!!!
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
Its the 3rd option.
As lets take ã as angular acceleration
Torque = ã × Moment of inertia
ã = T/ I
ã = 2 F R ÷ M R*2 / 2
ã = 4F/ MR
As Torque is F× R
And moment of ineria of disc is MR*2 /2
Question :-
Two equal and opposite forces are applied tangentially to a uniform disc of mass M and radius R as shown in figure .if the disc is pivoted at its centre and free to rotate in this plane, the angular acceleration of the disc is .. ?
Answer :-
Two forces applied on the disc but the direction is opposite ..
we get it ..
T ( torque) = 2FR
we applied moment of inertia on the solid and regular body (disc)
we get it ..
T(torque) = MR^2 × alpha / 2
alpha = angular acceleration.
for the solution see the adjoining attachment...