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Among Be, B, Mg and Al, the second ionization potential is maximum for
(a) B
(b) Be
(c) Mg
(d) Al
✨✨NOTE - EXPLAIN THE ANSWER MORE THAN THE 100 WORDS.✨✨
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❌❌NO SPAM❌❌
❌❌NO IRRELEVANT AND COPIED ANSWERS❌❌
Among Be, B, Mg and Al, the second ionization potential is maximum for
(a) B
(b) Be
(c) Mg
(d) Al
✨✨NOTE - EXPLAIN THE ANSWER MORE THAN THE 100 WORDS.✨✨
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When you remove 1 electron, among the above given elements, only boron attains a noble gas configuration and hence the most stable configuration of all.
We know that to remove an electron from a noble gas configuration, we need very high amount of energy.
Hence Boron will have the highest second ionization potential.
Answer is A.
this is because if you will remove one electron from these elements in the Boron will be the ideal gas which will have different calorific value.
from this the potential energy is being created.