P(6,-1),Q(1,3) and R(a,8) are points and if PQ=QR,then the value of a is ---
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P(6,-1),Q(1,3) and R(a,8) are points and if PQ=QR,then the value of a is ---
P(6,-1),Q(1,3) and R(a,8) are points and if PQ=QR,then the value of a is ---
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Answer:
PQ^2=(1-6)^2+(3+1)^2=25+16=41
QR^2=(a-1)^2+(8-3)^2=(a-1)^2+25
(a-1)^2+25=41
(a-1)^2=41-25=16
a-1=4, a=5
a-1= -4, a=-3
a= 5 and -3