(permutations and combinations)
• how many numbers can be formed from the digit 1,2,3,4,3,2,1, so those odd digits are at the odd places?
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(permutations and combinations)
• how many numbers can be formed from the digit 1,2,3,4,3,2,1, so those odd digits are at the odd places?
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Step-by-step explanation:
Number of ways so that odd digits are at the odd places
= P(4, 4) × P(3, 3) / 2! 2! 3!
= 4! × 3!/ 2×2×6
=24 × 6/ 24
= 6