Peter, Melanie, April and Jack received a total of 38 chocolate eggs. Jack had one less than Peter Peter had 5 less than Melanie Peter had 2 more than April How many eggs did April have?
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Peter, Melanie, April and Jack received a total of 38 chocolate eggs. Jack had one less than Peter Peter had 5
Let's use a system of equations to solve the problem:
Let's call the number of eggs that April had "A".
We know that Jack had one less than Peter, so Jack had "P-1" eggs.
We also know that Peter had 5 less than Melanie, so Peter had "M-5" eggs.
Finally, we know that Peter had 2 more than April, so Peter had "A+2" eggs.
We know that the total number of eggs is 38, so we can write an equation:
A + (P-1) + (M-5) + (A+2) = 38
Simplifying this equation, we get:
2A + P + M - 4 = 38
We also know that the total number of eggs is 38, so we can write another equation:
A + P + M + J = 38
Substituting "P-1" for "J", we get:
A + P + M + (P-1) = 38
Simplifying this equation, we get:
2P + M + A = 39
Now we have two equations:
2A + P + M - 4 = 38
2P + M + A = 39
We can solve this system of equations to find the values of A, P, and M. After solving, we get:
A = 8
P = 13
M = 18
Therefore, April had 8 chocolate eggs.