physics:- forces
A uniform metre rule of mass 100g is balanced on a fulcrum at 40 cm mark by suspending
an unknown mass m at 20 cm mark. Find the value of m. To which side the rule will tilt if
the mass is shifted to 10 cm mark. How can it be balanced by another mass of 50g ?
if u know then only answer this sum and pls show all the steps
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Given :-
To Find :-
(i) From the principle of moments,
Clockwise moment = Anticlockwise moment
(ii) The rule will tilt on the side of mass m (anticlockwise), if the mass m is moved to the mark 10cm.
(iii)Anticlockwise moment if mass m is moved to the mark
Resultant moment = 1500g cm − 1000g cm = 500g cm (anticlockwise)
(iv) From the principle of moments,
Clockwise moment = Anticlockwise moment
Let its distance from fulcrum be d cm.
Then,
By suspending the mass 50g at the mark 50 cm, it can be balanced.
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