playing urgent solve Q. 24 2nd part and Q. 28 fast
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playing urgent solve Q. 24 2nd part and Q. 28 fast
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Given time needed by the minutes hand show (t2/4) – 3 Hence the quadratic equation becomes, (t2/4) – 3 = 60 – t (t2– 12)/4 = 60 – t (t2 – 12) = 240 – 4 t t2 – 12 – 240 + 4 t = 0 t2 + 4t – 252 = 0 t2 + 18t – 14t – 252 = 0 t(t + 18) – 14(t + 18) = 0 (t + 18)(t – 14) = 0 (t + 18) = 0 or (t – 14) = 0∴ t = - 18 or t = 14 Since t cannot be negative, t = 14
number 28 is done in the above photographs
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