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Explanation:
1. Given that HCF = 9 and the numbers are 306 and 657.
LCM =?
We know that LCM* HCF= product of two numbers
→ LCM*9=306*657
→ LCM=201042/9=22338 .
2. If any number ends with the digit 0, it should be divisible by 10 or in other words, it will also be divisible by 2 and 5 as 10 = 2 × 5
Prime factorisation of 6n = (2 ×3)n
It can be observed that 5 is not in the prime factorisation of 6n.
Hence, for any value of n, 6n will not be divisible by 5.
Therefore, 6n cannot end with the digit 0 for any natural number n.
hope it helps u.
Answer:
the answer given above is correct