Please answer it fast question number 2 answer it fast
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Please answer it fast question number 2 answer it fast
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Question:-
In ΔABC, AD is the perpendicular bisector of BC (see the given figure). Show that ΔABC is an isosceles triangle in which AB = AC.
Step by Step explanation:-
Given :
In ΔABC, AD is the perpendicular bisector of BC.
To Prove :
ΔABC is an isosceles triangle in which AB = AC.
Solution :
In ΔADC and ΔADB,
AD = AD (Common)
∠ADC =∠ADB (Each 90º)
CD = BD (AD is the perpendicular bisector of BC)
∴ ΔADC ≅ ΔADB (By SAS congruence rule)
∴AB = AC (By CPCT)
Therefore, ABC is an isosceles triangle in which AB = AC.
Hence proved
Additional Information
(Figure in attachment)
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[tex]\large\underline\mathrm{GiVeN}[/tex]
[tex]\large\underline\mathrm{To\:PrOvE }[/tex]
[tex]\large\underline\mathrm{SoLuTiOn}[/tex]
In△ABD and △ACD
∠BAD = ∠CAD [ AD Bisects ∠A ]
AD = AD [ Common ]
∠ADB = ∠ ADC = 90° [ Given ]
So, △ABD ≅ △ACD [by ASA rule ]
So, AB = AC [ by CPCT ]
or, △ABC is an isosceles triangle.
[tex]<marquee>[/tex]hope it helps you.....✌✌