please answer it.pls do with steps
Share
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
B)1000
Step-by-step explanation:
v = u +at
v = 0 + 5 x 10
v = 50 m/s
By converting the given graph into velocity - time graph and obtaining the area underneath it we can find out the distance.
Answer:
option (B) 1000 m is correct
Step-by-step explanation:
since initial velocity (u)= 0
for first 10 sec.
velocity at the end of 10 seconds
( v) = at= 5×10
=> v= 50 m/sec
=> distance travelled= v²/2a
= 2500/10= 250m (1)
=> between 10 sec to 20 sec
acceleration= 0
=> the cart is moving with constant
velocity= 50m/sec
=> distance covered by cart between.
10 to 20 sec
= vel × time = 50×10= 500 m. ...........(2)
=> at last the graph is below =>
retardation
applied on the motion ,cart stopat the
end of 30 seconds
=> u= 50m/sec , t = 10 sec => v=0
=> distance covered in this situation
= u²/2a = 2500/10= 250m.................(3)
distance covered by the cart in 30 sec
= (1)+ (2) +(3)
= 1000 metre