please answer my question number 10 and explain it
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angleA+angleB+angleC=180
50+60+C=180
C=180-110
C=70
B. acute angled
C. isoceles
D. equlateral
E. 180/3=60
A) SUM OF TRIANGLE =18O
A + B + C = 180
50 + 60 + C = 180
11O + C = 180
THEREFORE, C = 180 -110
C = 70°
angle a = 60°
angle b = 50°
angle c = 70°
B)ACUTE - ANGLED
C)ISOSCELES
D)EQUILATERAL
E)180/3 = 60
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