please answer question 6b
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Given -
[tex] \sf v_{initial} = 25 \: ms^{-1} [/tex]
[tex] \sf v_{final} = 15 \: ms^{-1} [/tex]
[tex] \sf t_{initial} = 3 \: s [/tex]
[tex] \sf t_{final} = 4 \: s [/tex]
Solution -
Therefore,
acceleration,
[tex] \sf a = \dfrac{v_{final} - v_{initial}}{t_{final} - t_{initial}}[/tex]
[tex] \: \: \: \: \sf= \dfrac{15 - 25}{4 - 3} [/tex]
[tex] \: \: \: \: \sf = \dfrac{ - 10}{1} m {s}^{ - 2} [/tex]
[tex] \: \: \: \: \sf = - 10 \: m {s}^{ - 2} [/tex]
Answer -
Acceleration = -10 m/s²
i.e.: (retardation = 10 m/s²)
Answer:
ans is 90 -58% 58 24
Explanation:
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