please answer the above question fast. Best answer will be marked as brainliest(q. 16th)
please answer the above question fast. Best answer will be marked as brainliest(q. 16th)
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given - ABC and triangle DBC with same base BC.
prrove--ar(∆ABC)/ar(∆DBC =AO/DO
proofe we have ...
ar∆ABC=1/2 ×base ×height
ar∆ABC =1/2 ×BC ×AO ---------1)
and again in ∆DBC
ar ∆ DBC=1/2. × base ×height
ar∆DBC =1/2 ×BC ×DO-----------2)
now if we dividing the equation 1 and 2 we got .
ar ∆ABC /ar∆DBC =1/2 ×BC×AO/1/2 ×BC × DO
after cancelling all remaining is ..
ar∆ABC/ar∆DBC =AO/DO Prooved
hope it helps you !!
@Rajukumar111