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Answer:
1. x²-2x-8=0
x²-4x+2x-8=0
x(x-4)+2(×-4)=0
(x-4) (x+2) =0
x-4=0 》x=4 , x+2=0 》 x= -2
Verify
put,x=4 put,x= -2
then, 4²-2×4-8 then, (-2)²-2×(-2)-8
16 -8-8 4+4-8
16-16=0 8-8=0
So, 4and-2 are the zeros of x²-2x-8.