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Given :-
» 10^6 atoms weight 1.76×10^-16 gm.
Therefore,
» 1 atom will weight = [(1.76×10^-16)/10^6] = 1.76×10^-22 gm
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We know that :-
=> 1.66×10^-24 gm = 1 amu
so,
______________[ANSWER]
Thus atomic mass of silver = 106 amu
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[18]
» The balance reaction for the formation of CO2 is :-
C + O2 ==> CO2
» and For the formation of CO is
2C + O2 ==> 2CO
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» moles of CO2 in 88 gm of CO2 is = 88/44 = 2
» Hence 2 moles of O2 being used for the Formation of CO2
Now,
» 1 mole of O2 will give two moles of CO gas
» Hence molecular weight of CO gas is 28 gm/mol
» moles of O2 consumed in Formation of =
2× moles of CO formed
» Hence, 4 mole of CO gas is formed amount would be = 4×28 gm = 112 gm
_________[ANSWER]
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