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Answer:
a^3-4a^2+5a-6-(a^2-2a+1)
a^3-4a^2+5a-6-a^2+2a-1
a^3-5a^2+7a-7
Answer:
a³-5a²+6a-7.
Step-by-step explanation:
Le the required number to be subtracted be x.
Then, a³-4a²+5a-6-x=a²-2a+1
=>a³-4a²+5a-6-(a²-2a+1)=x
=>a³-4a²+5a-6-a²+2a-1=x
=>x=a³-5a²+6a-7
Therefore, the required number is a³-5a²+6a-7.