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Answer:-
(x+2),x,(2x+3)
If three are in an AP
[tex]\\ \tt{\:}\longrightarrow x-(x+2)=(2x+3)-x[/tex]
[tex]\\ \tt{\:}\longrightarrow x-x-2=2x+3-x[/tex]
[tex]\\ \tt{\:}\longrightarrow 0-2=2x-x+3[/tex]
[tex]\\ \tt{\:}\longrightarrow -2=x+3[/tex]
[tex]\\ \tt{\:}\longrightarrow -2-3=x[/tex]
[tex]\\ \tt{\:}\longrightarrow -5=x[/tex]
[tex]\\ \tt{\:}\longrightarrow x=-5[/tex]
Hence option B is correct option.