Please answer this question fast (with explaination)it is urgent
Share
Please answer this question fast (with explaination)it is urgent
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
GiVeN :-
✒ Speed of a cyclist is constant, which is = 5 m/s
✒ Diameter of the circular track = 70 m
To DeTeRmInE :-
The distance and displacement when the time is (a) 44 s (b) 66 s
SoLuTiOn :-
Perimeter of the track = length of the track
⇒Length = 2πr
⇒Length = 2 × 22/7 × 35 (Radius = 70/2 = 35)
⇒Length = 220 m
(a) Time(t) = 44 s,
Speed(v) = 5 m/s
Distance(s) = Speed × Time
⇒s = 44 × 5
⇒s = 220 m
Hence, in 44 s, the cyclist completes 1 round.
☛ As the cyclist completes 1 round in 44 s, then the displacement = 0
(Displacement is the shortest length of the path between the starting point and the final position.) As the starting point and the final point are the same, so
⇒Displacement = 0 m
(b) t = 66 s,
v = 5 m/s
s = v × t
⇒s = 5 × 66
⇒s = 330 m
☛ Therefore, in more 22 s, the cyclist covers 110 m more. That is, the cyclist covered a half round (full round = 200 m, half round = 110 m). Now, for a half round, displacement = Diameter of the circle.
⇒Displacement = 70 m