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Answer:
of 2nd question
Step-by-step explanation:
Answer of 1st question.
Let the digit in the unit's place be x and the digit in the ten's place be y. Then,
Number =10y+x
According to the given condition, we have
y=3x (i)
Number obtained by reversing the digits =10x+y
If the number is decreased by 54, the digits are reversed.
∴ Number −54= Number obtained by reversing the digits
⇒10y+x−54=10x+y
⇒9x−9y=−54⇒x−y=−6 (ii)
Putting y=3x in equation (ii), we get
x−3x=−6⇒x=3
Putting x=3 in y=3x, we get y=9
Hence, number =10y+x=10×9+3=93
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