please expand it in full process
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Verified answer
Answer:
(2x+y-3z)^2
using identity
=(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca
=(2x)^2+(y)^2+(3z)^2+2(2x)(y)+2(y)(3x)+2(3z)(2x)
=4x^2+y^2+9z^2+4xy+6yz+12xz
Answer:
4x^2 + 16 +9z^2
Step-by-step explanation:
(2x + 4 -3z)^2
(2x×2x + 4×4 -3z×-3z)
= 4x^2 + 16 + 9z^2
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