PLEASE explain me the step in which they opened the mod, how did they do that, tell me the logic and steps... please
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PLEASE explain me the step in which they opened the mod, how did they do that, tell me the logic and steps... please
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Let S be the set of all real roots of the equation, 3 (3-1)+2=13-1+13-21. Then, S (a) is a singleton (b) is an empty set (c) contains at least four elements (d) contains exactly two elements
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(b) is an empty set.
Step-by-step explanation:
To solve the equation, let's simplify both sides:
3(3 - 1) + 2 = 13 - 1 + 13 - 21
First, we simplify the left side:
3(2) + 2 = 6 + 2 = 8
Next, we simplify the right side:
13 - 1 + 13 - 21 = 12 - 8 = 4
So the equation becomes:
8 = 4
This equation is not true. In fact, it is a contradiction. Therefore, there are no real roots that satisfy the equation.
Hence, the set S of all real roots of the equation is an empty set.
Therefore, the answer is (b) is an empty set.