Please find the reading of the spring balance.
Share
Please find the reading of the spring balance.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
As per the given question ,
As the lift is moving in upward direction the normal force acts in upward direction the weight of the person acts in downward direction
hence ,
As the lift is moving with constant velocity the acceleration of the elevator is zero
The reading of the spring balance when lift is moving with uniform velocity in upward direction is 50 N
____________________
Let us consider that the lift is moving in upward direction with constant acceleration 'a'
hence ,
we know that ,
Hence rearranging 1 we get,
Now substituting the value of mg in the above equation we get ,
The reading of the spring balance when lift is moving with uniform acceleration in upward direction is 50(1+a/g) N