Please give me the correct answer of q.no.4 (b) I make u as brainleast guys please
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Please give me the correct answer of q.no.4 (b) I make u as brainleast guys please
Please give me the correct answer of q.no.4 (b) I make u as brainleast guys please
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x/3 - 1/3 -x/4 + 1/2 = 1
rearranging the terms
x/3 - x/4 -1/3 +1/2 =1
x/12 + 1/6 = 1
(x+2)/12 = 1
x+2=12
x=12-2
x=10
hope it helps
mark it as brainliest.......
Given:
To Find:
Answer:
Let us take the given equⁿ:-
[tex]\sf{\implies \dfrac{1}{3}(x-1)-\dfrac{1}{4}(x-2)=1 .}[/tex]
[tex]\sf{\implies \dfrac{x}{3}-\dfrac{1}{3}-\dfrac{x}{4}+\dfrac{2}{4}=1 .}[/tex]
( Opening the brackets )
[tex]\sf{\implies \dfrac{x}{3}-\dfrac{x}{4}-\dfrac{1}{3}+\dfrac{1}{2}=1.}[/tex]
(Grouping constant terms and variables .)
[tex]\sf{\implies \dfrac{4x-3x}{12}+\dfrac{-2+3}{6}=1.}[/tex]
[tex]\sf{\implies \dfrac{x}{12}+\dfrac{1}{6}=1 .}[/tex]
[tex]\sf{\implies \dfrac{x+2}{12}=1.}[/tex]
[tex]\sf{\implies x+2 = 12.}[/tex]
[tex]\sf{\implies x = 12-2.}[/tex]
[tex]\bf{\implies x=10.}[/tex]
Hence the value of x is 10.