please help me fast...................
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please help me fast...................
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Answer:
we know that AB||CD and t is a transversal cutting at E and F
From the figure we know that ∆BEF and ∆DFC are interior angle
SO, we get
∆BEF+∆DFE=189°
Dividing the entire equation by 2 we get
1/2 ∆BEF + 1/2 ∆DEF =90°
According to figure the above question can further be written as
∆GEF + ∆GFE = 90° .........(¡)
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