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Here it is interesting that the frequencies of the tuning forks are in AP with common difference 5!
Let the frequency of first tuning fork be,
a(1) = a
Then the frequency of the last (11th) one will be,
a(11) = a + (11 - 1) 5
a(11) = a + 10 × 5
a(11) = a + 50
Given that,
a(11) = 1.5 a(1)
a + 50 = 1.5 a
1.5a - a = 50
0.5a = 50
a(1) = 100 Hz
Thus the frequency of the first tuning fork is 100 Hz.
Then the frequency of the last tuning fork is,
a(11) = 150 Hz