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Answer:
triangke pqs =55+60+x=180
115 +x=180
180-115=a
a=b OPP angles are equl
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Answer:
a = 65°
b = 115°
c = 25°
Step-by-step explanation:
In ∆ PQS
a+ 60° + 55° =180° ( sum of all the angle of a ∆ is always 180°)
a + 115° = 180°
a= 180° - 115°
a = 65°
For line QS
a + b = 180° (Linear pair angle)
65° + b = 180°
b = 115°
In ∆PSR
40° + b + c = 180°
40° + 115° + c = 180°
155° + c = 180°
c = 180° - 155°
c = 25°