The current of 1A is flowing on the sides of an equilateral triangle of side 4.5 x [tex]10^{-2}[/tex] m. The magnetic field at the centre of the triangle will be:
a)2 x [tex]10^{-5}[/tex] Wb / [tex]m^{2}[/tex] b)Zero
c)8 x [tex]10^{-5}[/tex] Wb / [tex]m^{2}[/tex] d)4 x [tex]10^{-5}[/tex] Wb /[tex]m^{2}[/tex]
Please help me wid this question I think the answer is option d) but I'm not sure:/
Please help me Nilesh if u know the answer it's important pls
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☆ ANSWER ☆
You are right !
Option D) 4 × 10^-5 is the answer.
Oh dear ! why you waited for me ? I wasn't online that time. It's a Biot-Savart law question and our textbooks have pretty much solved examples for reference. I too use the same - Particular formula, calculator and sometimes for reference I go with the solved example or theory.
BTW congrats for your new rank !
Keep growing
Have a pleasant evening