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Answer:
Explanation:
Given : Molarity of H2SO4 = 18M
As, Molarity = volume of solutionno. of moles of solute
i.e., 18moles of sulphuric acid is present per litre of solution.
Density=1.8g/mL {given}
Thus , mass of one litre of this solution ,
Density = volumemass
mass = density×volume
mass = 1.8×1000
mass = 1800g
Thus , mass of 1litre 18M H2SO4 solution is 1800g or 1.8kg.
Now, mass of solution = mass of solute + mass of solvent
mass of solution = no. of moles of solute X molar mass of solute + mass of solvent
1800 = 18×98 + mass of solvent
mass of solvent = (1800−1764)g
mass of solvent = 36g
Now , molality of H2SO4 solution is given by,
molality = massofsolvent(inkg)numberofmolesofsolute
molality = 3618×100
molality = 500m
Hence, the molality of H2SO4 solution is 500m.