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Answer:
3) Let x = 1 and y = 4
4x - ky = 5 ------(1)
Substituting values of x and y in equation (1)
4(1) - k(4) = 5
4 - 4k = 5
-4k = 5 - 4
-4k = 1
k = -1/4
4) Let x = 4 and y = 5
4x - 5y = 12
4(4) - 5(5) = 12
16 - 25 = 12
-9 ≠ 12
Therefore they are not the zeroes.
Verified answer
Step-by-step explanation:
3)
4x-ky=5 and (1,4) is solution then put x=1 and y=4
4(1)-k(4)=5
4k=4-5=-1
therefore k=-1/4
4)
put x=4 and y=5 in eqn
4(4)-5(5)-12=16-25-12=-21 not equal to zero so it is not a solution.
5)
refer image
hope this helps