PLEASE HELP ME with this question GuYS. I hope you all will help
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PLEASE HELP ME with this question GuYS. I hope you all will help
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Answer:
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Step-by-step explanation:
to prove: ∠adc= ∠ acd
given: ∠1= ∠2, ∠b= ∠3
in triangle ebc ,
∠6+ ∠b+ ∠1+ ∠2=180° {angle sum property}
replacing ∠ B with ∠ 3
∠6+ ∠1+ ∠2+ ∠3=180°
since ∠,1= ∠2 hence ∠ 2+ ∠1 can be written as 2∠1
∠6+2 ∠1+ ∠3=180°------------{1}
now in triangle edc ,
∠4+ ∠6+ ∠1=180°{angle sum property}
∠6=180-{ ∠1+ ∠4}------------{2}
from{2}
180-{ ∠1+ ∠4}+2 ∠1+ ∠3=180°
2 ∠1+ ∠3= ∠1+ ∠4 + 180-180
2 ∠1- ∠1+ ∠3= ∠4
∠1+ ∠3= ∠4
hence proved , ∠ adc= ∠acd
to prove: Zadc= z acd
given: 21= 22, zb= 23
in triangle ebc,
26+ ab+ Z1+ 2=180° {angle sum
property}
replacing z B with 2 3
26+ Z1+ 22+ 43=180°
since 2,1= L2 hence z 2+ 21 can be
written as 241
26+2 21+ 43=180°----- --{1}
from{2}
180-{ 21+ 24}+2 21+ 23=180°
2 21+ 23= 21+ 4 + 180-180
2 21- 21+ 23= 24
21+ 23= 24
hence proved , 2 adc= Zacd
Step-by-step explanation:
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