please please please help me out to solve this question please
Share
please please please help me out to solve this question please
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Step-by-step explanation:
Consider △ADP & △QBC
∠D=∠B (Opposite side of parallelogram.)
∴DA=BC (Opposite side of parallelogram.)
∠x=∠x [bisector of opposite angle.]
∴ By ASA congruence rule. [△ADP≅△QBP]
then by CPCT, DP=QB⟶(1)
∠x=∠x [bisector of opposite angle.]
△ADP≅△QBP [by ASA]
AB=DC [opposite side of a parallelogram.]
AQ+QB=DP+PC [QB=DP from 1]
AQ=PC⟶(2)
Hence distance between AP and QC are equal at all place hence proved AP∥QC⟶(3)
∴AQCP is parallelogram.