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Answer:
Step-by-step explanation:
1. Let n+1,n+3,n+5,n+7,n+9,n+11,n+13,n+15------eq(1) be 8 odd numbers.
then sum of these 8 odd numbers is 64
n+1+n+3+n+5+n+7+n+9+n+11+n+13+n+15=64
8n+64 = 64
8n = 64-64
n = 0
substitute n=0 in eq(1)
∴ The 8 odd numbers are 1,3,5,7,9,11,13,15
∴ 1+3+5+7+9+11+13+15=64
2. Let n+1, n+3, n+5, n+7, n+9, n+11, n+13, n+15, n+17, n+19, n+21------eq(1) be 11 odd numbers.
then sum of these 11 odd numbers is 121
n+1+n+3+n+5+n+7+n+9+n+11+n+13+n+15+n+17+n+19+n+21=121
11n+121 = 121
11n = 121-121
n = 0
substitute n=0 in eq(1)
∴ The 11 odd numbers are 1,3,5,7,9,11,13,15,17,19,21
∴ 1+3+5+7+9+11+13+15+17+19+21=121
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