please poora solve krke bhejna
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Question: A body is moving from d1 = 6i + 4j - 3k to d2 =8i + 2j - 2k under the action of a constant force 2i + 4j - 5k. Find the workdone
Answer:
1 joule
Explanation:
Displacement = d₂ - d₁
= (8i + 2j - 2k) - (6i + 4j - 3k)
= (8 - 6)i + (2 - 4)j + (-2 + 3)k
= 2i - 2j - k
Work done = force x displacement
= (2i + 4j - 5k) x (2i - 2j - k)
= (2 x 2) + (4 x (-2)) + (-5 x (-1))
= 4 - 8 + 5
= 1
Workdone is 1 joule.
(however, if that =* means +, answer would be 4-8-5 = - 9 joule)