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Answer :
Number are 4 & 5.
Step-by-step explanation:
Let one number be x
Then, second number = 9-x
A. T. Q
Sum of their squares is equal to 41
Then,
[tex] {x}^{2} + ({9 - x})^{2} = 41[/tex]
[tex] {x}^{2} + {x}^{2} + 81 - 18x = 41[/tex]
[tex]2 {x}^{2} - 18x = 41 - 81[/tex]
[tex]2 {x}^{2} - 18x = - 40[/tex]
[tex]2 {x}^{2} - 18x + 40 = 0 \\ 2( {x}^{2} - 9x + 20) = 0[/tex]
[tex] {x}^{2} - 9x + 20 = 0[/tex]
☆ From Splitting Method.
[tex] {x}^{2} - 4x - 5x + 20 = 0 \\ x(x - 4) - 5(x - 4) = 0 \\ (x - 5)(x - 4)[/tex]
[tex] \huge{\it {\underline{\underline{\red{\bold {So, \:one\:number \:is\: 5}}}}}} [/tex]
[tex] \huge{\it {\underline{\underline {\red{\bold {and\:another \:number \:is \:4}}}}}} [/tex]
Thank You.
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