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Answer:
The quadratic polynomial is x^2+9x+20= 0x^2+9x+20=0
Step-by-step explanation:
To find : Quadratic polynomial whose zeroes are -4,-5 ?
Solution :
If \alphaα and \betaβ are the zeroes of a quadratic equation,
Then the quadratic polynomial can be written as
x^2-x(\alpha+\beta )+\alpha\beta = 0x ^2 −x(α+β)+αβ=0
According to question, \alpha =-4,\beta =-5α=−4,β=−5
Substitute the values,
x^2-x(-4-5)+(-4)(-5)= 0x ^2 −x(−4−5)+(−4)(−5)=0
x^2-x(-9)+20= 0x ^2 −x(−9)+20=0
x^2+9x+20= 0x^2 +9x+20=0
Therefore, the quadratic polynomial is x^2+9x+20= 0x^2+9x+20=0
From a quadratic polynomial whose zeroes are 5 and-5
Answer:
X2 +9x+ 20
Step-by-step explanation:
sum roots = 9
product of roots= 20
since, quadratic polynomial is ad
x2- ( sum of roots) X + product of roots
so, x2 + 9x+ 20