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Answer:
answer is 65 degree
Step-by-step explanation:
quadrilateral PQOR
1-∠OQP is 90° since a tangent to a circle is perpendicular to the radius through the point of contact.
2-Similarly ∠ ORP is 90° d since a tangent to a circle is perpendicular to the radius.
3- therefore angle ROQ is =360° - (90°+90°+50°) (50° is given of PQOR )
= 360° - 230°
= 130°
∠QSR = 130°÷2 because ∠QSB is inscribed angel
= 65° Inscribed angel is half the a center angle that subtends the
same arc .
Answer is 65°